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x^2+9=x-3x-39
We move all terms to the left:
x^2+9-(x-3x-39)=0
We add all the numbers together, and all the variables
x^2-(-2x-39)+9=0
We get rid of parentheses
x^2+2x+39+9=0
We add all the numbers together, and all the variables
x^2+2x+48=0
a = 1; b = 2; c = +48;
Δ = b2-4ac
Δ = 22-4·1·48
Δ = -188
Delta is less than zero, so there is no solution for the equation
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